Problem
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.You should preserve the original relative order of the nodes in each of the two partitions.
For example,
Given 1->4->3->2->5->2 and x = 3,
return 1->2->2->4->3->5.
Idea
- Create another linked list. Firstly, put all node < x into the new list. Then put all nodes >x into the new list.
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